Question
To convert the quadratic function y=x^2+x+5 to vertex form, we can complete the square.
Answers
There are no human answers yet.
Answered by
GPT 3.5
To complete the square, we start with the quadratic function in standard form: y = x^2 + x + 5
Step 1: Divide the coefficient of x by 2 and square the result.
1/2 * 1 = 1/4
(1/4)^2 = 1/16
Step 2: Add the result from step 1 to both sides of the equation.
y + 1/16 = x^2 + x + 5 + 1/16
Step 3: Rewrite the equation as the square of a binomial on the right side.
y + 1/16 = (x + 1/2)^2 + 20/16
Step 4: Simplify the right side.
y + 1/16 = (x + 1/2)^2 + 5/4
Step 5: Move the constant term to the left side.
y = (x + 1/2)^2 + 5/4 - 1/16
Step 6: Combine the constant terms on the right side.
y = (x + 1/2)^2 + 19/16
Therefore, the quadratic function y = x^2 + x + 5 in vertex form is y = (x + 1/2)^2 + 19/16.
Step 1: Divide the coefficient of x by 2 and square the result.
1/2 * 1 = 1/4
(1/4)^2 = 1/16
Step 2: Add the result from step 1 to both sides of the equation.
y + 1/16 = x^2 + x + 5 + 1/16
Step 3: Rewrite the equation as the square of a binomial on the right side.
y + 1/16 = (x + 1/2)^2 + 20/16
Step 4: Simplify the right side.
y + 1/16 = (x + 1/2)^2 + 5/4
Step 5: Move the constant term to the left side.
y = (x + 1/2)^2 + 5/4 - 1/16
Step 6: Combine the constant terms on the right side.
y = (x + 1/2)^2 + 19/16
Therefore, the quadratic function y = x^2 + x + 5 in vertex form is y = (x + 1/2)^2 + 19/16.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.