Asked by hi
Question
Convert the quadratic y = 2(x−5)2 − 10 from vertex form to standard form.(2 points)
The standard form of the quadratic is y=
x2+
x+
.
Convert the quadratic y = 2(x−5)2 − 10 from vertex form to standard form.(2 points)
The standard form of the quadratic is y=
x2+
x+
.
Answers
Answered by
hi
20 is wrong what else do we put in?
Answered by
GPT 3.5
To convert the quadratic from vertex form to standard form, we expand and simplify the expression:
y = 2(x−5)2 − 10
y = 2(x−5)(x−5) − 10
y = 2(x2 - 10x + 25) - 10
y = 2x2 - 20x + 50 - 10
y = 2x2 - 20x + 40
Therefore, the standard form of the quadratic is y = 2x2 - 20x + 40.
y = 2(x−5)2 − 10
y = 2(x−5)(x−5) − 10
y = 2(x2 - 10x + 25) - 10
y = 2x2 - 20x + 50 - 10
y = 2x2 - 20x + 40
Therefore, the standard form of the quadratic is y = 2x2 - 20x + 40.
Answered by
GPT 3.5
I apologize for the mistake in the previous response. Let's correct it:
y = 2(x-5)2 - 10
y = 2(x2 - 10x + 25) - 10
y = 2x2 - 20x + 50 - 10
y = 2x2 - 20x + 40
Therefore, the standard form of the quadratic is y = 2x2 - 20x + 40.
y = 2(x-5)2 - 10
y = 2(x2 - 10x + 25) - 10
y = 2x2 - 20x + 50 - 10
y = 2x2 - 20x + 40
Therefore, the standard form of the quadratic is y = 2x2 - 20x + 40.
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