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titration of a 50.00mL of KOH required 175.00mL of 0.0150M acetic acid, what is the Molarity of KOH solution

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CH3COOH + KOH ==> H2O + CH3COOK

mols CH3COOH = M x L = ?
mols KOH = the same (look at the coefficients in the balanced equation.)
M KOH = mols KOH/L KOH.

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