Total resistance R = 6R₁
P = E^2/R, so
120^2/6R₁ = 200
solve for R₁
the current is 120/6R₁, so use that for each resistor, P = I^2 R
P₁ = 120/6R₁ * R₁ = 20
and so on for the other two resistors
12
Three resistors R₁, R₂, and R, are connected in series and to a 120-volt source. If R₂ = 2R₁, R3 = 3R₁,
and the total power taken by the circuit is 200 watts, calculate (a) the resistance of each resistor, (b) the power in each resistor.
1 answer
1 answer