Three point sized bodies each of mass M are fixed at three corners of light triangular frame . In the above problem about an axis perpendicular to the plane of frame and passing through a corner of frame the moment of inertia of three bodiea is ??

Answer 1

simple. EAch point will give 1/2 M distance^2. So one point will have zero distance(the axis is thru that point), so the other two will give 1/2 M (s1^2 + s2^2) where s1 and s2 are the distances form each M to the axis.