Three point sized bodies each of mass M are fixed at three corners of light triangular frame of length L about an axis perpendicular to the plane of frame passing through centre of frame the moment of inertia of three bodies is

Ans : MLsquare

2 answers

Oh come on, I already did two of these. Now all three masses are L/sqrt 3 from the axis

3 M (L/sqrt3)^2 = 3 ML^2 /3 = M L^2
damon could u plss tell how all three masses are l /sqr 3