These two articles should get you started, if you haven't yet read your course materials ...
https://www.electronics-tutorials.ws/accircuits/parallel-circuit.html
https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/calculating-power-factor/
Three impedances zL=3+j4 ohms, zC=4-j4 ohms and zR=0+j3 ohms are connected in parallel. solve for the power factor of the combination.
2 answers
Given:
zL = 3+j4 Ohms.
zC = 4-j4 Ohms.
zR = 3+j0? Ohms.
(3+j4)(4-j4)/(3+j4+4-j4) = (12-j12+j16+16)/7 = (28+j4)/7=4+j4/7 =
zL in parallel with zC.
Z = 3(4+j4/7)/(3+4+j4/7) = (12+j12/7/(7+j4/7) = 12+j12/(7+j4) = 17[45o]/8.06[29.7 = 2.1Ohms[15.3o]
Power Factor = Cos15.3 = 0.96.
zL = 3+j4 Ohms.
zC = 4-j4 Ohms.
zR = 3+j0? Ohms.
(3+j4)(4-j4)/(3+j4+4-j4) = (12-j12+j16+16)/7 = (28+j4)/7=4+j4/7 =
zL in parallel with zC.
Z = 3(4+j4/7)/(3+4+j4/7) = (12+j12/7/(7+j4/7) = 12+j12/(7+j4) = 17[45o]/8.06[29.7 = 2.1Ohms[15.3o]
Power Factor = Cos15.3 = 0.96.
1 answer