Asked by liz
Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ∘C, the total pressure in the container is 4.50atm . Calculate the partial pressure of each gas in the container.
Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane.
Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane.
Answers
Answered by
DrBob222
Use PV = nRT and solve for n = total mols
mols CH4 = grams/molar mass = ?
mols C2H6 = grams/molar mass = ?
mols unknown gas = total mols - mols CH4-mols C2H6.
mol fraction = XCH4 = mols CH4/total mols.
XC2H6 = mols C2H6/total mols
Xunknown = mols unkn/total mols
pCH4 = XCH4*Ptotal
pC2h6 = XC2H6*Ptotal
punk = Xunk*Ptotal
mols CH4 = grams/molar mass = ?
mols C2H6 = grams/molar mass = ?
mols unknown gas = total mols - mols CH4-mols C2H6.
mol fraction = XCH4 = mols CH4/total mols.
XC2H6 = mols C2H6/total mols
Xunknown = mols unkn/total mols
pCH4 = XCH4*Ptotal
pC2h6 = XC2H6*Ptotal
punk = Xunk*Ptotal
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.