Asked by emmanuel
Three gases (8.00 of methane, , 18.0 of ethane, , and an unknown amount of propane, ) were added to the same 10.0- container. At 23.0 , the total pressure in the container is 3.50 . Calculate the partial pressure of each gas in the container.
Answers
Answered by
bobpursley
Partial pressure is divided according to mole ratio.
Figure out the moles of each, than add to get total moles.
pressuremethane= molesmethane/totalmoles * total pressure
pressurethane= moleethane/totalmoles * total pressure
and so on. until you get the ones you know.
then pressure propane= total pressure-sum of partial pressures ethane, methane, ...
Figure out the moles of each, than add to get total moles.
pressuremethane= molesmethane/totalmoles * total pressure
pressurethane= moleethane/totalmoles * total pressure
and so on. until you get the ones you know.
then pressure propane= total pressure-sum of partial pressures ethane, methane, ...
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