Three designs are proposed for an engine that is to operate between 500 and 300 K. Design A is claimed to produce 750 J of work per kilojoule of heat input, B is claimed to produce 500 J, and C is claimed to produce 250J. Which design would you choose?

3 answers

efficiency=(500-300)/300=.67
work output= 1000*eff=670 J
so the first design A is baloney
so go with design B would be my choice.
what formula did u use?
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