Asked by Taylor
This one confused me since it revolved around what seemed like dividing trig function by another function
Write the following expression in terms of the tangent function
2 / ((cos(r^2 - s^2) / (sin(r^2 - s^2))
= ?
I know tan t = sin t / cos t. So would I multiply by the reciprocal? Or since cos / sin = cot would I put the 2 over cotangent. this one confused me
Write the following expression in terms of the tangent function
2 / ((cos(r^2 - s^2) / (sin(r^2 - s^2))
= ?
I know tan t = sin t / cos t. So would I multiply by the reciprocal? Or since cos / sin = cot would I put the 2 over cotangent. this one confused me
Answers
Answered by
Reiny
2 / ((cos(r^2 - s^2) / (sin(r^2 - s^2))
= 2 * (sin(r^2 - s^2) / (cos(r^2 - s^2)
= 2 tan (r^2 - s^2)
= 2 * (sin(r^2 - s^2) / (cos(r^2 - s^2)
= 2 tan (r^2 - s^2)
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