|AC|^2 = 40^2 + 45^2 = 1600+2025
so
|AC| = 60.2 meters
Now this is the same as the problem below this one
draw a line through A perpendicular to AC
Now with trig the problem is trivial, but I will assume you must stick to geometry
let AP = x
then
CP = (60.2 - x)
call the altitude we want h
then
h^2 + x^2 = 40^2 = 1600
h^2 +(60.2-x)^2 = 45^2 = 2025
so
(60.2-x)^2 -x^2 = 2025-1600
3625 -120.4x = 425
x = 26.57
well so
26.57^2 + h^2 = 1600
h = 29.9
this is pathegreom theorem
22. Points A, B, and C are corners of a triangular field where mABC is 90°, AB is 40 meters and BC is 45 meters.
a) Find the length of AC .
A
40 m
B 45 m C b) John walks along the edge of the field from point A to point C. If P is
the point on AC when John is nearest to point B, find the length of BP.
2 answers
Hey, give me the whole problem the first time. When I did the one below you did not say angle was right angle at B