*This is part of an exam. so please don't give full solution* just trying to bump ahead of a block.

The decomposition of NO2 at room temperature exhibits the following variation in concentration with time:

The concentration of NO2 is expressed in mol/liter, while time is expressed in seconds.
[NO2] ln[NO2] 1/[NO2] Time (s)
0.0831 -2.4877 12.03 0
0.0666 -2.7091 15.02 4.2
0.0567 -2.8700 17.64 7.9
0.0487 -3.0221 20.53 11.4
0.0441 -3.1213 22.68 15.0

We have to obtain reaction order.

From my attempts this is not 1st nor 2nd order.
I'm trying with Differential method.

ln (-dC/dt) = alpha * ln(C) + ln(k)

but plotting ln (-dC/dt) vs ln(C) doesn't give a straight line.

???

6 answers

I think I would try converting concn and time to change in rate and plot change in rate vs concn.
you mean without ln,
just dC/dt over C ?

not a straight line.

I've searched around and I am under the impressione that even if values don't align perfectly people still say it's second order reaction, is it?

ratio of (1/t)/t are as follow:
0.7119
0.7081
0.8257
0.5972

not particularly a straight line, isn't it?
A straight line parallel to x axis is zero order.
A straight line between x and y axis passing through zero is 1 st order (like a Beer's Law plot)
A curved line is second order.
First of all thanks for your help.

I meant that reading around the web, NO2 at room tempearature is said to be a second order rection.
If it was such, the graph of 1/C vs time should be a straight line, whose k is the rate.
I did that, and those values are near but not particularly a straigth line.

ratio of (1/C)/t are as follow:
0.7119
0.7081
0.8257
0.5972

Anyway, starting with first table, so you think this is a second order reaction?
*so, do
Reaction is second order, even if your plot of 1/T doesn't give a perfectly straigth line.

a) 2

b) 0.71

my reagrds to will
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