Driving in your car with a constant speed of v= 22 m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure (Figure 1) .

Question

Part A
If the radius of curvature of the bump is 52 m, find the apparent weight of a 66-kg person in your car as you pass over the top of the bump.

Answer 1

While the car is driving on the bump, a centripetal acceleration acts toward the center of the radius of curvature. Take the direction toward the center as positive, this is also the direction of the weight of the person. The apparent weight of the person will be equal to the normal force. From Newton's 2nd law:

∑F(c) = ma(c) = mg - n
n = mg - ma(c)

But a(c), centripetal acceleration, is equal to v²/r, so:

n = mg - mv²/r
= m(g - v²/r)
= 67kg[9.8m/s² - (12m/s)²/35m]
= 380N (properly rounded)

Hope this helps.

Answer 2

lol u put 12m/s instead of 22m/s

Answer 3

ok but why

Answer 4

just why

Answer 5

I hate physics

Answer 6

bababooey

Answer 7

Ava wants to figure out the average speed she is driving. She starts checking her car’s clock at mile marker 0. It takes her 4 minutes to reach mile marker 3. When she reaches mile marker 6, she notes that 8 minutes total have passed since mile marker 0.
What is the average speed of the car in miles per minute?
mile(s) per minute
What is an equation of the line that represents n, the number of mile marker passed, as a function of t, time in minutes?

Help me plz

Answer 8

...............................thx 4 the help