HNO3/CU(NO3)2 = 4 mols /1 mol
so
6/x = 4/1
4 x = 6
x = 1.5
This is a stoichiometry equation.
Cu(s) + 4(HNO3)(aq) -> Cu(NO3)2(aq) + 2(NO2)(g)+2(H2O)(l)
If you use 6 moles of nitric acid 4(HNO3), how many moles of Copper (II) Nitrate Cu(No3)2 will be produced?
1 answer