Hg(ℓ) + NO3^ (–1) (aq) + Cl^(–1) (aq) → HgCl4^(–2) (s) + NO2(g)
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NO3^- + 1e + 2H^+ ==> NO2 + H2O
Hg + 4Cl^- ==> HgCl4^2- + 2e
I have separated into the two half equations and I've balanced each.
Multiply equation 1 by 2 and add to equation 2 for the complete equation.
Cancel the two electrons on each side for the final equation.
this is a repost.
Balance the following ionic equation for acidic conditions. Identify the oxidizing agent and the reducing agent. Show the steps.
Hg(ℓ) + NO3^ (–1) (aq) + Cl^(–1) (aq) → HgCl4^(–2) (s) + NO2(g)
2 answers
I guess I'm 223 but you got an answer.
2 answers