Thought I answered this
-x/e^x
e^x >> x for large x
This is a question related to L'hopital's rule.
lim x -> -infinity of ((x)(e^x))
This thing is weird because I apply l'hopital's rule yet I never receive the correct answer which is supposedly = 0. It just stays in the form [-infinity * -infinity].
Anyone can help out?
5 answers
How did you get that Damon? I thought I could only reorder question as e^x/(1/x) and apply hopital rule from there
e^x as x --> big negative is 1/e^big negative
e^-a = 1/e^a
I mean
e^x as x --> big negative is 1/e^big positive
e^x as x --> big negative is 1/e^big positive