Question

This is a question related to L'hopital's rule.

lim x -> -infinity of ((x)(e^x))

This thing is weird because I apply l'hopital's rule yet I never receive the correct answer which is supposedly = 0. It just stays in the form [-infinity * -infinity].

Anyone can help out?

Answer 1

Thought I answered this
-x/e^x
e^x >> x for large x

Answer 2

How did you get that Damon? I thought I could only reorder question as e^x/(1/x) and apply hopital rule from there

Answer 3

e^x as x --> big negative is 1/e^big negative

Answer 4

e^-a = 1/e^a

Answer 5

I mean
e^x as x --> big negative is 1/e^big positive