I think you mean
y = a x^2 + b x + c
y = 0 at x=2/3 and at x=-4
(x-2/3)(x+4) = 0
(3x-2)(x+4) = 0
3 x^2 +10 x - 8 = 0
so y =3 x^2 + 10 x - 8
THINKING QUESTION
Create a quadratic equation in the form ax² + bx + c = 0 that crosses through the points (2/3, 0), and (-4, 0). The variables a, b, and c must be integers (whole numbers).
2 answers
You are given 2 intercepts, so we could just write
a(x+4)(3x - 2) = 0
since a is a constant, a ≠ 0, we could divide both sides by a
(x+4)(3x-2) = 0
3x^2 + 10x - 8 = 0
a(x+4)(3x - 2) = 0
since a is a constant, a ≠ 0, we could divide both sides by a
(x+4)(3x-2) = 0
3x^2 + 10x - 8 = 0
3 answers