I have to assume you know the chain rule.
if x is a function of t, and f is a function of x, then
df/dt=df/dx * dx/dt
this is a fundamental relationship in calculus.
These questions relate to curvature problems.
a.Explain why (dÖ/ds) = (dÖ/dt) (dt/ds).
b.Explain why tanÖ = dy/dx, which equals (dy/dt) / (dx/dt).
5 answers
I understand that much, but I still cannot derive the curvation equation..
a.Let x prime and x double prime be the first derivative and second derivatives of x with respect to t, and similarly for y. Show the following in true.
dƒ³/ds = ( x�Œ y�Œ�Œ - x�Œ�Œ y�Œ ) / (vector V)^3
a.Let x prime and x double prime be the first derivative and second derivatives of x with respect to t, and similarly for y. Show the following in true.
dƒ³/ds = ( x�Œ y�Œ�Œ - x�Œ�Œ y�Œ ) / (vector V)^3
Wow that did not work...
Prove
(dphi/ds) = ( xprime*ydouble prime - xdoubleprime*yprime ) / (vector V)^3
Prove
(dphi/ds) = ( xprime*ydouble prime - xdoubleprime*yprime ) / (vector V)^3
x prime. OK that is the first derivative of x with respect to ???
same for double prime. Your statement is just totally meaningless, it cant be proved unless it is understood.
same for double prime. Your statement is just totally meaningless, it cant be proved unless it is understood.
I am trying to prove the formula..
2 answers