Theresa has $26 in her wallet. The bills are worth either $5 or $1. If there are 14 bills total, how many does she have of each type?

Answer 1

Set up your given:
Let x be $5
Let y be $1
Amount: 5x + y = 26
Number of bills: x + y = 14

Solve the equations by elimination:
(multiply the first equation by -1 to make y negative.. it would then cancel out)
-5x - y = -26
x + y = 14
-4x = -12
x = 3

Plug in x to any of your orig. equations
x + y = 14
$5 = 3
$1 = 14-3
= 11

Check: 3 $5 bills and 11 $1 bills equal to 14 bills.
Check: 3x$5 = $15
11x$1 = $11
$15 + $ 11 = $26

Answer 2

Is it 3 fives and 11 ones