Let's assume the student has x $1 bills and y $5 bills.
We know that the student has a total of 15 bills, so we can write the equation x + y = 15. (Equation 1)
We also know that the total amount of money in the wallet is $47, so we can write the equation 1x + 5y = 47. (Equation 2)
Now we can solve the system of equations using substitution or elimination.
Substitution:
From Equation 1, we can rewrite x = 15 - y.
Substituting this value of x into Equation 2:
1(15 - y) + 5y = 47
15 - y + 5y = 47
15 + 4y = 47
4y = 47 - 15
4y = 32
y = 32/4
y = 8
Substituting this value of y back into x = 15 - y:
x = 15 - 8
x = 7
Therefore, the student has 7 $1 bills and 8 $5 bills.
A student has some $1 bills and $5 bills in his wallet. He has a total of 15 bills that are worth $47. How many of each type of bill does he have?
1 answer
1 answer