There were 610 people at a play. The admission price was $3.00 for adults and $1.00 for children. The admission receipts were $1,250.00. How many adults and children attended?

2 answers

a + c = 610, therefore c = 610 - a

3a + c = 1250

Substitute 610-a for c in second equation and solve for a. Insert that value into the first equation and solve for c. Check by inserting both values into the second equation.
290 children---- 290X 1.00= 290
320 adults ----- 320X 3.oo= 960
therefore 290+ 960= 1250