a. L = 120yds * 3ft./yd = 360 Ft.
W = 53 1/3yd * 3ft/yd = 160 Ft.
b. Length = 2L + 2W = 2*360 + 2*160 = 1040 Ft. = Perimeter.
c. 5,280Ft/mi * 1Lap/1040Ft = 5.1 Laps/m1. or 5.1 Laps = 1 mile.
There is a football field and the length shows 120 yd and the width is 53 1/3 yd
a. What are the dimensions of a football field in feet?
b. A chalk line is placed around the perimeter of the football field. What is the length of this line in feet?
c. About how many laps around the perimeter of the field would equal 1 mile. Explain?
I am somewhat confused on these math questions and don't know exactly how to attempt solving this problem.
Please help.
18 answers
B. 1040.
a. 160 feet (53 1/3 yd.) and 360 feet 120 yds.)
b. 1,040 feet
c. ???
b. 1,040 feet
c. ???
It is 1040 for b
thank you this rilly help me
I dont understand how to easily explain the last problem (c) please help. My homework is due tomorrow and this is a important grade
thank you so much
what sup
hey you wrong number b because they say what is the length of this line in feet so number b is 720 feet
a. 600 w, 700L
b. 50 x 70 x 60 x 90= 500
c. 5000
b. 50 x 70 x 60 x 90= 500
c. 5000
A. 160 feet to 360 feet
B. 1,040 feet
C.5.5 laps
B. 1,040 feet
C.5.5 laps
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Thanks
can you guys stop being useless and answer Letter C
A. 160ft:360ft
B. 1040ft
C. About 5 miles
B. 1040ft
C. About 5 miles
I need help on part C. can somebody answer correctly.
I made a 100! On my test thx so much all of the answers were right except for yens