1.00*avgweight=.187*41+.436*42+.377*44
Put this into your google search windown:
.187*41+.436*42+.377*44=
There are three naturally occurring isotopes
of the hypothetical element hilarium 41Hi, 42Hi, and 44Hi. The percentages of these
isotopes are the following:
Hilarium Natural
Isotopes Abundance
41Hi 18.7%
42Hi 43.6%
44Hi 37.7%
You can assume that the atomic masses are exactly equal to the mass number. Calculate
the weight of “naturally” occurring hilarium and report it as you would for any other naturally occurring element. Answer in units of g/mol. Your answer must be within ± 0.005%
2 answers
42.57