a) 11 + 1 (you) = 12. 12/80 = 0.15 = 15%
b)40% = 0.4, 0.4 x 80 = 32.
c) 7.5% = 0.075, 0.075 x 80 = 6
Also, 0.5% x 80 = 0.005 x 80 = 0.4 students, which doesn't make sense.
there are 80 students enrolled in statistics. (a)you and 11 other earned the same score. what percent of the class received your score? (b)forty percent of the class received a grade of C. how many students received a C? (c) only 7.5% of the class received a D. how many students is this? A student claims that .5% of the class failed. why is this impossible?
5 answers
fill in missing proportion for normal distribution.
1. .40
2. .10
1. .40
2. .10
see a.) if .15 = 15%, which is correct, then .5 is 50% not .005, therefore, 4 students failed but, we have calculated that 65% of the students have a grade above failing. The claim that 50% failed is false, there is only 35% left who have a grade other than the D and some other grade different than the 15% that is, 12 of 80 or 12/80.
72%
If the class inclues you ... then how can it be a pool of 80 ? the pool would have to be 79 and only 11 students got your score ?
1 answer