There are a total of 10 fruits in the basket.
The probability of selecting a pear on the first draw is 6/10.
After selecting a pear, there are 9 fruits left in the basket, including 4 apples.
The probability of then selecting an apple on the second draw is 4/9.
To find the probability of both events happening together, we multiply the probabilities:
6/10 * 4/9 = 24/90 = 4/15
Therefore, the probability of randomly selecting a pear, not replacing it, and then selecting an apple is 4/15.
There are 4 apples and 6 pears I. A fruit basket. What is the probability of randomly selecting a pear, not replacing it then selecting an apple?
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1 answer