There are 3 consecutive even integers such that the quotient obtained by dividing twice the largest integer by the smallest integer is three less than three-fifths of the second integer. What are the integers?

Answer 1

Three consecutive even integers are:
2n, 2n+2, 2n+4, where n is an integer.

The rule is thus:
2(2n+4)/2n = (3/5)(2n+2) - 3

Rearranging gives:
0 = 6 n² - 19n - 20

Find the integer root(s) of this quadratic. Solve for integer n.

Use n to find the three consecutive even numbers.

Answer 2

I would let my 3 consecutive even integers be
x-2, x, and x+2

2(x+2)/(x-2) =3x/5 - 3
expanding and collecting like terms gives us
3x^2 - 31x + 10 = 0
(x-10)(3x - 1) = 0
x = 10 or x = 1/3, but x is an integer, so

x = 10

the integers are 8, 10 , and 12