Asked by Jake

There are 10 colored balls in a box ( 5 red, 3 blue, 2 green ). What is the probability of picking out a red ball and then a blue ball ( If I do not replace the red ball
Answered by PsyDAG
red ball = 5/10, blue ball = 3/9

The probability of all events occurring is found by multiplying the probabilities of the individual events.
Answered by ray nicholson
6. A bowl contains 10 red balls, 10 green balls and 10 white balls.
a. What is the probability of drawing 2 white balls with replacement?
b. What is the probability of drawing 2 white balls without replacement?
Answered by Anonymous
9+853412
Answered by Kevin
a. Probability of drawing a white ball is 10(number of white balls)/ 30 (total number of balls) since the balls are replaced, the probability remains the same for the second ball, that is 10/30. To determine probability of drawing balls with replacement is found by multiplying both probabilities (10/30)*(10/30)

b. Probability of drawing without replacement is slightly different from with replacement. The first white ball is still 10/30 but the second will be the number of remaining white balls (9) divided by the remaining number of total balls (29). To determine probability, multiply the probabilities of each individual event. Thus, (10/30)*(9/29)
Answered by Laura
(5*3)/(10*9)=1/6
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