The width is 30 cm and there are two sides at 30 cm. Those two sides = 60 cm.
Call the length X and there are two of them so 60 + 2X = 88 for the perimeter.
Solve for X. I get 29 cm but you should verify that. Therefore anything longer than 29 cm for the length will have a perimeter greater than 88 cm. Check my work.
the width of a rectangle is fixed at 30cm. What lengths will make the perimetear greater than 88cm
3 answers
30+30+2x>88; 30+30=60; 60-(30+30)+2x>88; 2x/2>28/2; x>14. > is greated than
ii need roux
pls HELELPFE pls im dum
pls HELELPFE pls im dum