The width of a rectangle is 20m less than twice its length. If the perimeter of the rectangle is more than 56m, find the minimum dimensions of the rectangle if each dmension in meters is an integer.

Answer 1

length ----x m
width ---- 2x-20 m

2x + 2(2x-20) > 56
6x - 40 > 56
6x > 96
x > 16

min length is 17m, min width is 14 m

note, a length of 16 and a width of 12 would give you an exact perimeter of 56, but it said it had to be greater than 56 , and the sides had to be integers.