I would use PV = nRT and solve for P. If pressure is greater than 23.76 torr, there will be liquid present.
Using PV = nRT, plug in 23.76 converted to atm and solve for n = moles H2O in vapor. Subtract from moles in 1.25 initially. The difference is amount water liquid left.
The water vapor pressure at 25 degrees celsius is 23.76 torr. If 1.25 grams of water is enclosed in a 1.5 L container, will any liquid be present? If so, what mass of liquid?
2 answers
1.204 g