If you had shown what you did we could tell you what you did wrong.
moles C3H8O3 = grams/molar mass
moles H2O = (338 mL*0.992 g/mL)/molar mass
mole fraction H2O = moles H2O/total moles.
vap pressure water = moles fraction H2O x normal vap pressure water. I get 49.96 in a quickie calculation which rounds to 50.0 torr. You should do it more accurately than I.
The answer is 50.0 torr and I got 46.0 torr but idk what I did wrong.
Find the vapor pressure of a solution of 164 g of C3H8O3 and 338 mL of water at 39.8 degrees Celsius. Water's VP at 39.8 degrees celsius is 54.74 torr; it's density is 0.992 g/mL.
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