Ecell = (-0.592/2)log(dil/conc)
0.023 = (-0.0592/2)log(0.1/x)(
Solve for x = approximately 0.6 M
The voltage generated by the zinc concentration cell described by,
Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s)
is 23.0 mV at 25°C. Calculate the concentration of the Zn2 (aq) ion at the cathode.
Can someone please breakdown how to do this so I can figure out the rest of these types of Questions on my own?
Thank you.
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