The voltage generated by the zinc concentration cell described by,

Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s)

is 24.0 mV at 25 °C. Calculate the concentration of the Zn2 (aq) ion at the cathode.

How would I go about this problem? I am extremely confused :/

Thank you so much in advance!!!

1 answer

Ecell = (-0.0592/2)log Q
You know Ecell is 0.024 v
Q from the equation you wrote is
(?Zn^2+)/(Zn^2+ 0.1) or it may be better to write Q as
Q = (x/0.1) and solve for x = ?M Zn^2+ on the right hand side of the equation. Post your work if you get stuck.
Similar Questions
  1. The voltage generated by the zinc concentration cell described by,Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s) is 23.0 mV at 25
    1. answers icon 2 answers
  2. The voltage generated by the zinc concentration cell (described by,Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s)) is 27.0 mV at
    1. answers icon 2 answers
  3. The voltage generated by the zinc concentration cell described by,Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s) is 11.0 mV at 25
    1. answers icon 1 answer
  4. The voltage generated by the zinc concentration cell described by,Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s) is 21.0 mV at 25
    1. answers icon 1 answer
more similar questions