Ecell = (-0.0592/2)log Q
You know Ecell is 0.024 v
Q from the equation you wrote is
(?Zn^2+)/(Zn^2+ 0.1) or it may be better to write Q as
Q = (x/0.1) and solve for x = ?M Zn^2+ on the right hand side of the equation. Post your work if you get stuck.
The voltage generated by the zinc concentration cell described by,
Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s)
is 24.0 mV at 25 °C. Calculate the concentration of the Zn2 (aq) ion at the cathode.
How would I go about this problem? I am extremely confused :/
Thank you so much in advance!!!
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