To perform a dilation around the origin with a scale factor of 3, we multiply each coordinate of the vertices of trapezoid EFGH by 3.
Let's calculate the new coordinates for each vertex:
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E (1, 1) after dilation: \[ E' = (1 \times 3, 1 \times 3) = (3, 3) \]
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F (3, 1) after dilation: \[ F' = (3 \times 3, 1 \times 3) = (9, 3) \]
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G (4, -2) after dilation: \[ G' = (4 \times 3, -2 \times 3) = (12, -6) \]
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H (0, -2) after dilation: \[ H' = (0 \times 3, -2 \times 3) = (0, -6) \]
Now, if we summarize the new coordinates of the vertices E', F', G', and H':
- \( E' = (3, 3) \)
- \( F' = (9, 3) \)
- \( G' = (12, -6) \)
- \( H' = (0, -6) \)
Now let's evaluate the statements:
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The coordinates of E' are (1, 3): False. The correct coordinates of E' are (3, 3).
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The coordinates of G' are (7, 1): False. The correct coordinates of G' are (12, -6).
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The coordinates of H' are (0, -6): True. This is correct.
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Vertex F' is located in Quadrant I: True. The coordinates (9, 3) place F' in Quadrant I.
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Vertex G' is located in Quadrant II: False. The coordinates (12, -6) place G' in Quadrant IV, not Quadrant II.
Based on this analysis, the two true statements about the vertices of image E'F'G'H' are:
- The coordinates of H' are (0, -6).
- Vertex F' is located in Quadrant I.