Question
The vertices of trapezoid EFGH are located at E (1, 1), F (3, 1), G (4, -2), and H (0, -2). After EFGH has been dilated with a scale factor of 3 about the origin, which two statements are true about the vertices of image E'F'G'H' ?
The coordinates of E' are (1, 3).
The coordinates of G' are (7, 1).
The coordinates of H' are (0, -6).
Vertex F' is located in Quadrant I.
Vertex G' is located in Quadrant II.
The coordinates of E' are (1, 3).
The coordinates of G' are (7, 1).
The coordinates of H' are (0, -6).
Vertex F' is located in Quadrant I.
Vertex G' is located in Quadrant II.
Answers
GPT-4o mini
To determine the coordinates of the vertices of trapezoid EFGH after a dilation with a scale factor of 3 about the origin, we can apply the dilation transformation to each vertex. The formula for dilating a point \((x, y)\) by a scale factor \(k\) about the origin is given by:
\[
(x', y') = (kx, ky)
\]
Using this formula, let's calculate the new coordinates for each vertex:
1. **For vertex E (1, 1)**:
\[
E' = (3 \times 1, 3 \times 1) = (3, 3)
\]
2. **For vertex F (3, 1)**:
\[
F' = (3 \times 3, 3 \times 1) = (9, 3)
\]
3. **For vertex G (4, -2)**:
\[
G' = (3 \times 4, 3 \times -2) = (12, -6)
\]
4. **For vertex H (0, -2)**:
\[
H' = (3 \times 0, 3 \times -2) = (0, -6)
\]
Now, summarizing the coordinates of the vertices of the dilated trapezoid E'F'G'H':
- \(E'\) is (3, 3)
- \(F'\) is (9, 3)
- \(G'\) is (12, -6)
- \(H'\) is (0, -6)
Now, let's evaluate the given statements:
1. **The coordinates of E' are (1, 3).**
- **False**; the coordinates of \(E'\) are (3, 3).
2. **The coordinates of G' are (7, 1).**
- **False**; the coordinates of \(G'\) are (12, -6).
3. **The coordinates of H' are (0, -6).**
- **True**; the coordinates of \(H'\) are correct.
4. **Vertex F' is located in Quadrant I.**
- **True**; \(F' (9, 3)\) is located in Quadrant I.
5. **Vertex G' is located in Quadrant II.**
- **False**; \(G' (12, -6)\) is located in Quadrant IV.
Based on this analysis, the two true statements are:
- The coordinates of H' are (0, -6).
- Vertex F' is located in Quadrant I.
\[
(x', y') = (kx, ky)
\]
Using this formula, let's calculate the new coordinates for each vertex:
1. **For vertex E (1, 1)**:
\[
E' = (3 \times 1, 3 \times 1) = (3, 3)
\]
2. **For vertex F (3, 1)**:
\[
F' = (3 \times 3, 3 \times 1) = (9, 3)
\]
3. **For vertex G (4, -2)**:
\[
G' = (3 \times 4, 3 \times -2) = (12, -6)
\]
4. **For vertex H (0, -2)**:
\[
H' = (3 \times 0, 3 \times -2) = (0, -6)
\]
Now, summarizing the coordinates of the vertices of the dilated trapezoid E'F'G'H':
- \(E'\) is (3, 3)
- \(F'\) is (9, 3)
- \(G'\) is (12, -6)
- \(H'\) is (0, -6)
Now, let's evaluate the given statements:
1. **The coordinates of E' are (1, 3).**
- **False**; the coordinates of \(E'\) are (3, 3).
2. **The coordinates of G' are (7, 1).**
- **False**; the coordinates of \(G'\) are (12, -6).
3. **The coordinates of H' are (0, -6).**
- **True**; the coordinates of \(H'\) are correct.
4. **Vertex F' is located in Quadrant I.**
- **True**; \(F' (9, 3)\) is located in Quadrant I.
5. **Vertex G' is located in Quadrant II.**
- **False**; \(G' (12, -6)\) is located in Quadrant IV.
Based on this analysis, the two true statements are:
- The coordinates of H' are (0, -6).
- Vertex F' is located in Quadrant I.
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