The vertices of a triangle are A(1,2), B(4,2), and C (4,6). What is the length of the hypotenuse?

Very confused HELP!!!

2 answers

hyp. = AC = sqrt((4-1)^2+(6-2)^2) =
A and B have the same y-coordinate ... AB parallel to x-axis

B and C have the same x-coordinate ... BC parallel to y-axis

AB and BC are perpendicular ... AC is the hypotenuse
... looks like a 3-4-5 triangle