the velocity of the water jet discharging from the orifice can be obtained from v = (2gh)^(1/2), where h = 2m is the depth of the orifice from the free water surface. determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits the surface.
2 answers
That will depend upon how far below the orifice that point B is. A figure should tell you that. We cannot see your figure.
Vx = sqrt(2gh)
y=y0 + Vy *t - 1/2gt^2
-1.5= -1/2gt^2
solve for t
t= 0.553
x=x0 + vx*t ,x0 = 0
x=3.4641m
y=y0 + Vy *t - 1/2gt^2
-1.5= -1/2gt^2
solve for t
t= 0.553
x=x0 + vx*t ,x0 = 0
x=3.4641m
0 answers