Question

The velocity of an object is found to be 𝑣(𝑡) = 12√𝑡 + 4 meters per second at time 𝑡
seconds. If at time 𝑡 = 1 seconds, the object is located at position 𝑠(1) = 1 meters, find the
position of the object at time 𝑡 = 4 seconds.

Answer 1

s(t) = 8t^(3/2) + 4t + c
use s(1) = 1 to find c
then find s(4)

Answer 2

To find C, I can do this right?

y=8t^(3/2) + 4t + C = 1 = 8(1^(3/2)) + 4(1) + C = -11

Answer 3

yes, C = -11, but you do play fast and loose with those = signs ...