Question
An object initially traveling at a velocity of 20.0 meters per second undergoes uniform acceleration for 5.0 seconds, reaching a final velocity of 50.0 meters per second. What is the acceleration of the object?(1 point)
Responses
6.0 m/s2
6.0 m/s 2
4.0 m/s2
4.0 m/s 2
10.0 m/s2
10.0 m/s 2
14 m/s2
Responses
6.0 m/s2
6.0 m/s 2
4.0 m/s2
4.0 m/s 2
10.0 m/s2
10.0 m/s 2
14 m/s2
Answers
GPT-4o mini
To find the acceleration of the object, we can use the formula for acceleration \( a \):
\[
a = \frac{v_f - v_i}{t}
\]
Where:
- \( v_f \) is the final velocity (50.0 m/s),
- \( v_i \) is the initial velocity (20.0 m/s), and
- \( t \) is the time (5.0 seconds).
Now, plug in the values:
\[
a = \frac{50.0 \, \text{m/s} - 20.0 \, \text{m/s}}{5.0 \, \text{s}} = \frac{30.0 \, \text{m/s}}{5.0 \, \text{s}} = 6.0 \, \text{m/s}^2
\]
Thus, the acceleration of the object is \( \boxed{6.0 \, \text{m/s}^2} \).
\[
a = \frac{v_f - v_i}{t}
\]
Where:
- \( v_f \) is the final velocity (50.0 m/s),
- \( v_i \) is the initial velocity (20.0 m/s), and
- \( t \) is the time (5.0 seconds).
Now, plug in the values:
\[
a = \frac{50.0 \, \text{m/s} - 20.0 \, \text{m/s}}{5.0 \, \text{s}} = \frac{30.0 \, \text{m/s}}{5.0 \, \text{s}} = 6.0 \, \text{m/s}^2
\]
Thus, the acceleration of the object is \( \boxed{6.0 \, \text{m/s}^2} \).