The velocity graph of a particle moving along the x-axis is shown. The particle has zero velocity at t=0.00s and reaches a maximum velocity, vmax, after a total elapsed time, t total. If the initial position of the particle is x0 =9.35m, the maximum velocity of the particle is vmax=29.3m/s, and the total elapsed time is t total=29.9s, what is the particle's position at t=19.9s?
4 answers
the graph is not shown.
the graph is a straight line
If the velocity versus time is straight, then its slope, the acceleration, is constant
a = change in v/change in t
= (29.3 - 0)/29.9
calculate a
v = Vi + a t
but Vi = 0
so at t = 19.9
v = 0 + a (19.9)
a = change in v/change in t
= (29.3 - 0)/29.9
calculate a
v = Vi + a t
but Vi = 0
so at t = 19.9
v = 0 + a (19.9)
the graph is not shown.
0 answers