The velocity function is v(t)=t^2-5t+6 for a particle moving along a line. Find the displacement of the particle during the time interval [-3,6].

Answer 1

s(t) = 1/3 t^3 + 5/2 t^2 + 6t
evaluate s(6)-s(-3)

not sure what negative time involves, but hey, it's just math...