Asked by REALLY NEED HELP!!!!
The velocity function is v(t)= t^2-5t+ 4 for a particle moving along a line. The position function s(t) is an antiderivative of the velocity function. Find the displacement, s(6) - s(-3), by the particle during the time interval [-3,6].
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Answered by
bobpursley
what is the derivative of 1/3 t^3-5/2 t^2+4t+ C ?
Answered by
REALLY NEED HELP!!!!
That's the problem. I have no idea. The question is exactly like i posted it here. I did the same thing but i realized i wasn't given a value of what it should equal to. I was hoping there a different way of solving this problem
Answered by
REALLY NEED HELP!!!!
Never mind i got it.
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