Asked by TNT
The velocity as a function of time for a car on an amusement park ride is given as v = At2 + Bt with constants A = 2.9m/s3 and B = 1.3m/s2. If the car starts at the origin, what is its position at t = 4.2s?
Answers
Answered by
Damon
v = A t^2 + B t
v = 2.9 t^2 + 1.3 t
then assuming you know how to integrate
x = (2.9/3)t^3 + (1.3/2) t^2 + c
if x = 0 at t = 0, then c = 0
x = 0.967 t^3 + 0.65 t^2
put in t = 4.2
v = 2.9 t^2 + 1.3 t
then assuming you know how to integrate
x = (2.9/3)t^3 + (1.3/2) t^2 + c
if x = 0 at t = 0, then c = 0
x = 0.967 t^3 + 0.65 t^2
put in t = 4.2
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