displacement is ∫[0,3] v dt
but since v < 0 at t = 2/3,
total distance is ∫[9,2/3] v dt + ∫[2/3,3] -v dt
The velocity function, in feet per second, is given for a particle moving along a straight line.
v(t) = 3t − 2, 0 ≤ t ≤ 3
Find the displacement
15/2
Find the total distance that the particle travels over the given interval
Im not sure how to do this one
2 answers
oops just backwards, since v < 0 until t = 2/3
5 answers