velocity of a particle- the displacement s (in meters) of a particle moving in a straight line is given by the equation of motion s=4t^3+6t+2, where t is measured in seconds. Find the velocity of the particle s at times t=a t=1 t=2 t=3
5 answers
same as the one before
thanks
im stuck still
s = 4t^3 + 6t + 2
ds/dt = v = 12t^2 + 6
when t = 1, v = 12(1^2) + 6 = 18
when t = 2, v = ....
when t = 3 .......
when t = a , b = 12a^2 + 6
ds/dt = v = 12t^2 + 6
when t = 1, v = 12(1^2) + 6 = 18
when t = 2, v = ....
when t = 3 .......
when t = a , b = 12a^2 + 6
thank you