Psoln = Xip*Poip
Xpropyl = 0.250; therefore, Xipropyl = 0.750
Plug into the above.
Check my thinking.
The Vapor pressures of pure propyl alcohol and isopropyl alcohol are 21.0 mmHg and 45.2 mmHg, respectively, at 25 (degrees)C. Calculate the partial pressure of isopropyl alcohol above a solution in which the mole fraction of propyl alchol is 0.250.
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