The vapor pressure of pure methanol at 25 degrees Celsius is 127.2 mm Hg. If 12.20 g of potassium chloride are dissolved in 200.0 g of methanol, what is the vapor pressure of the solution?

Question

The vapor pressure of pure methanol at 25 degrees Celsius is 127.2 mm Hg. If 12.20 g of potassium chloride are dissolved in 200.0 g of methanol, what is the vapor pressure of the solution?
A.123.9 mmHg
B.3.256 mmHg
C.104.3 mmHg
D142.7 mmHg

DrBob222 · Answer

mols KCl = grams/molar mass = ? mols methanol = grams/molar mass = ? Xmethanol = mols methanol/total mols. p(methanol) = i*X.methanol i is 2 for KCl Post your work if you get stuck.

Kaitlyn · Answer

I didn't get any of the answer choices I got 1.95 It's .164 mol kcl 6.242 mol ch3oh Then put the 6.242 over 6.406 and got .975 Then 2 x the .975

DrBob222 · Answer

I gave you the wrong formula. Let me start over.

bobpursley · Answer

I don't get close to any of those answers.