Asked by Stephany

The vapor pressure of pure ethanol at 20 degrees C is 44 mmHg, and the vapor pressure of pure methanol at the same temperature is 94 mmHg. In a solution of the two, the mole fraction of ethanol is .439; the mole fraction for methanol is .561. Calculate the vapor pressure of each component of the solution.

Answers

Answered by DrBob222
P<sub>ethanol</sub> = X<sub>ethanol</sub>*P<sup>o</sup><sub>ethanol</sub>
The methanol is done the same way.
Answered by DrBob222
P<sub>ethanol</sub> means partial pressure of the ethanol above the solution.
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