The vapor pressure of water at 45.0 °C is 71.93 mmHg. What is the vapor pressure of water over a solution prepared from 75.0 g of citric acid (C6H8O7) in 0.420 kg of water at this temperature?

Answer 1

P_H2O> = X_H2O>*^{o</sup_H2O
mols H2O = g/molar mass = 420/18 = ?
mols C6H8O7 = g/molar mass = 75.0/192 = ?
Total mols = mols H2O + mols C6H8O7 = ?
X_{H2O</sub = mols H2O/total mols
Calculate mols H2O, mols C6H8O7, total mols, then XH2O
Substitute into equation 1 and solve.
Post your work if you get stuck.}}

Answer 2

Let me try again. I tried to type in subscripts and superscripts and that didn't work well because I didn't do it right. I think you can interpret this OK. If not let me know.
PH2O = X^o_H2O
mols H2O = g/molar mass = 420/18 = ?
mols C6H8O7 = g/molar mass = 75.0/192 = ?
Total mols = mols H2O + mols C6H8O7 = ?
XH2O = mols H2O/total mols
Calculate mols H2O, mols C6H8O7, total mols, then XH2O
Substitute into equation 1 and solve.
Post your work if you get stuck.

Answer 3

Sorry again. Replace equation 1 with the following:
P_H2O = X_H2O*Psup>oH2O

Answer 4

those closing tags are a pain, right? :-(

Answer 5

A REAL pain.